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You are watching: Find the area of the parallelogram with vertices a(−3, 0), b(−1, 6), c(8, 5), and d(6, −1).

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Cristiano Sears
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Vertices are(A(-3,0), B(-1,6), C(8,5))and(D(6,-1))

So

(vecAB==)

(vecAD==)

Hence area of parallelogram

(=|vecAB imesvecAD|)

(vecAB imesvecAD=eginbmatrixi&j&k\2&6&0\9&-1&0endbmatrix)

(=i(0-0)+j(0-0)+k(-2-54))

(=-56k)

Hence

Area(=|vecAB imesvecAD|)

(=sqrt(-56)^2=56)


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