because that reference:In figure ABCD is a parallelogram and also the triangle APB, AQD and also CRD are equilateral. Uncover x. (answer: \$120^circ\$)

My progress:I found the complying with links and also put it in the drawing\$AF = FC\BF = FD\measuredangle QEG = 60^o\measuredangle DAC = measuredangle ACB\$

but ns can"t finish..

You are watching: Find the measure of angle x in the figure below:

So \$ riangle PAQ cong riangle poor \$ and also hence \$angle AQP = angle ADB\$

Similarly show that \$ riangle RDQ cong riangle CDA\$ and also so, \$angle DQR = angle CAD\$

But \$angle ADB + angle CAD = 180^circ - x \$ (see \$ riangle AOD\$ whereby \$O\$ is the allude of intersection that diagonals in the parallel \$ABCD\$)

\$angle PQR = x = 180^circ - x + 60^circ implies x = 120^circ\$

Thanks for contributing an answer to 4476mountvernon.com Stack Exchange!

But avoid

Asking because that help, clarification, or responding to other answers.Making statements based upon opinion; earlier them up with referrals or personal experience.

Use 4476mountvernon.comJax to style equations. 4476mountvernon.comJax reference.

See more: Madonna Exposes Fans Breast Uncensored, Madonna Exposes Fan'S Breast During Concert

To find out more, watch our tips on writing good answers.

## Not the price you're spring for? Browse various other questions tagged geometry or questioning your very own question.

site style / logo © 2021 ridge Exchange Inc; user contributions license is granted under cc by-sa. Rev2021.10.19.40496

4476mountvernon.comematics stack Exchange works finest with JavaScript permitted