In this article, we will certainly learn how to evaluate and also solve logarithmic attributes with unknown variables.

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**Logarithms and exponents space two object in mathematics that are closely related. **Therefore it is valuable we take a brief review the exponents.

An exponent is a form of writing the recurring multiplication the a number by itself. One exponential function is the the kind f (x) = b y, where b > 0 because that example, 32 = 2 × 2 × 2 × 2 × 2 = 22.

The exponential duty 22 is read as “**two raised by the exponent the five**” or “**two raised to strength five**” or “**two raised to the 5th power.**”

On the various other hand, the logarithmic duty is defined as the inverse function of exponentiation. Take into consideration again the exponential duty f(x) = by, where b > 0 b x

Then the logarithmic function is given by;

f(x) = log b x = y, wherein b is the base, y is the exponent, and x is the argument.

The function f (x) = log b x is check out as “log base b that x.” Logarithms are valuable in mathematics due to the fact that they permit us to carry out calculations through very big numbers.

## How to deal with Logarithmic Functions?

To fix the logarithmic functions, it is necessary to usage exponential features in the offered expression. The herbal log or *ln* is the inverse of *e*. That method one have the right to undo the various other one i.e.

ln (e x) = x

e ln x = x

To solve an equation through logarithm(s), the is important to know their properties.

### Properties the logarithmic functions

Properties the logarithmic attributes are just the rules for simplifying logarithms once the inputs are in the type of division, multiplication, or index number of logarithmic values.

*Some that the properties are detailed below.*

**Product rule**

The product preeminence of logarithm claims the logarithm of the product of two numbers having a common base is same to the sum of separation, personal, instance logarithms.

⟹ log in a (p q) = log a p + log in a q.

**Quotient rule**

The quotient preeminence of logarithms states that the logarithm the the two numbers’ ratio with the same bases is same to the difference of every logarithm.

⟹ log a (p/q) = log in a p – log in a q

**Power rule**

The power ascendancy of logarithm states that the logarithm of a number through a rational exponent is same to the product of the exponent and its logarithm.

⟹ log in a (p q) = q log a p

**Change of base rule**

⟹ log a p = log in x p ⋅ log in a x

⟹ log in q ns = log x ns / log x q

**Zero Exponent Rule**

⟹ log p 1 = 0.

*Other nature of logarithmic attributes include:*

log a a = 1

Logarithms that 1 to any kind of base are 0.log a 1 = 0

Log*a*0 is undefinedLogarithms of negative numbers space undefined.The base of logarithms deserve to never be an adverse or 1.A logarithmic role with base 10is called a common logarithm. Always assume a basic of 10 once solving through logarithmic attributes without a little subscript because that the base.

### Comparison the exponential function and logarithmic function

Whenever you view logarithms in the equation, you always think of exactly how to cancel the logarithm to settle the equation. Because that that, you usage an **exponential function**. Both that these features are interchangeable.

The complying with table speak the means of writing and **interchanging the exponential functions and logarithmic functions**. The 3rd column tells around how to check out both the logarithmic functions.

Exponential function | Logarithmic function | Read as |

82 = 64 | log 8 64 = 2 | log base 8 the 64 |

103 = 1000 | log 1000 = 3 | log basic 10 of 1000 |

100 = 1 | log 1 = 0 | log basic 10 of 1 |

252 = 625 | log 25 625 = 2 | log basic 25 that 625 |

122 = 144 | log 12 144 = 2 | log base 12 of 144 |

Let’s use these nature to deal with a pair of problems involving logarithmic functions.

*Example 1*

Rewrite exponential function 72 = 49 come its equivalent logarithmic function.

Solution

Given 72 = 64.

Here, the basic = 7, exponent = 2 and also the discussion = 49. Therefore, 72 = 64 in logarithmic role is;

⟹ log in 7 49 = 2

*Example 2*

Write the logarithmic tantamount of 53 = 125.

Solution

Base = 5;

exponent = 3;

and discussion = 125

53 = 125 ⟹ log 5 125 =3

*Example 3*

Solve for x in log 3 x = 2

Solution

log 3 x = 232 = x⟹ x = 9

*Example 4*

If 2 log x = 4 log 3, then uncover the value of ‘x’.

Solution

2 log in x = 4 log in 3

Divide every side by 2.

log x = (4 log in 3) / 2

log x = 2 log in 3

log x = log 32

log x = log 9

x = 9

*Example 5*

Find the logarithm that 1024 come the base 2.

Solution

1024 = 210

log 2 1024 = 10

*Example 6*

Find the value of x in log 2 (*x*) = 4

Solution

Rewrite the logarithmic duty log 2(*x*) = 4 come exponential form.

24 = *x*

16 = *x*

*Example 7*

Solve for x in the following logarithmic function log 2 (x – 1) = 5.

SolutionRewrite the logarithm in exponential form as;

log 2 (x – 1) = 5 ⟹ x – 1 = 25

Now, resolve for x in the algebraic equation.⟹ x – 1 = 32x = 33

*Example 8*

Find the value of x in log x 900 = 2.

Solution

Write the logarithm in exponential type as;

x2 = 900

Find the square root of both sides of the equation to get;

x = -30 and also 30

But since, the base of logarithms have the right to never be negative or 1, therefore, the exactly answer is 30.

*Example 9*

Solve for x given, log in x = log in 2 + log in 5

Solution

Using the product dominion Log b (m n) = log in b m + log b n we get;

⟹ log in 2 + log in 5 = log (2 * 5) = Log (10).

Therefore, x = 10.

*Example 10*

Solve log x (4x – 3) = 2

Solution

Rewrite the logarithm in exponential form to get;

x2 = 4x – 3

Now, solve the quadratic equation.x2 = 4x – 3x2 – 4x + 3 = 0(x -1) (x – 3) = 0

x = 1 or 3

Since the basic of a logarithm have the right to never be 1, climate the just solution is 3.

*Practice Questions*

*Practice Questions*

1. Refer the adhering to logarithms in exponential form.

a. 1og 26

b. Log 9 3

c. Log4 1

d. Log 66

e. Log 825

f. Log 3 (-9)

2. Settle for x in every of the complying with logarithms

a. Log in 3 (x + 1) = 2

b. Log 5 (3x – 8) = 2

c. Log (x + 2) + log in (x – 1) = 1

d. Log in x4– log in 3 = log(3x2)

3. Uncover the worth of y in every of the adhering to logarithms.

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a. Log in 2 8 = y

b. Log 5 1 = y

c. Log in 4 1/8 = y

d. Log in y = 100000

4. Settle for xif log x (9/25) = 2.

5. Solve log 2 3 – log 224

6. Discover the worth of x in the following logarithm log 5 (125x) =4

7. Given, log in 102 = 0.30103, log 10 3 = 0.47712 and Log 10 7 = 0.84510, resolve the following logarithms: